document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26300>Question 26300</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I could really use some help!!<BR>\n" );
document.write( "Here is my question:Find the two-digit number whose tens digit is 4 less than its unit digit if the original number is 2 more than 3 times the sum of the digits.<BR>\n" );
document.write( "I don't even know where to start! PLEASE HELP!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14136 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two-digit number be ab (a is the ten's digit; b is the unit's digit)<BR>\n" );
document.write( "EQUATIONs:<BR>\n" );
document.write( "a=b-4<BR>\n" );
document.write( "10a+b is the value of the number \"ab\" just as 23=10*2+3.<BR>\n" );
document.write( "Therefore 10a+b=3(a+b)+2<BR>\n" );
document.write( "10a+b=3a+3b+2<BR>\n" );
document.write( "7a-2b=2<BR>\n" );
document.write( "Now you have two equations; solve by substitution, as follows:<BR>\n" );
document.write( "7(b-4)-2b=2<BR>\n" );
document.write( "7b-28-2b=2<BR>\n" );
document.write( "5b=30<BR>\n" );
document.write( "b=6<BR>\n" );
document.write( "Since a=b-4, a=6-4=2<BR>\n" );
document.write( "Solution is a=2, b=6<BR>\n" );
document.write( "The two-digit number is 26<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );