document.write( "Question 188497: I am having a hard time trying to factor this equation. (x²-x+1)
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document.write( "Im starting to think it is prime but I'd like to make sure.
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document.write( "This is how i worked it out.
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document.write( "i know that each set of parantheses will start out with \"x\". then i would figure out what times what will give you a positive one and subtract to give you a negative one. If you could please explain to me how to come about getting this answer, that would be greatly apprciated. \n" );
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Algebra.Com's Answer #141325 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The short answer is that this trinomial is prime, meaning that it is not factorable over the integers. In fact, this one isn't factorable over the real numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This might be getting a little ahead of you, given the way you phrased the question, but it is something that you will be learning in a week or two anyway. What I'm talking about is a little trick to determine the character of the roots of a quadratic equation of the form:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the coefficient on the x term and square it: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Multiply 4 times the lead coefficient times the constant term: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Find the difference of these two values: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the result is zero, then you have a perfect square trinomial, and this would be factorable over the integers..\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the result is positive and a perfect square, then the trinomial is factorable over the integers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the result is positive and not a perfect square, the factors are real but irrational numbers, i.e. they involve the square root of a quantity that is not a perfect square. For the time being, you would consider such a trinomial as prime.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If the result is less than zero, then the factors are complex numbers of the form \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, just to illustrate with your problem:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "and your factors would contain a conjugate pair of complex numbers; they would look like:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Like I said, the trinomial is prime as far as you are concerned.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |