document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188473>Question 188473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this linear system using substitution?\r<BR>\n" );
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document.write( "3/8x + 3/4y = 12<BR>\n" );
document.write( "2/3x + 1/2y = 13 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141311 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141311\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do you solve this linear system using substitution? <BR>\n" );
document.write( "3/8x + 3/4y = 12<BR>\n" );
document.write( "2/3x + 1/2y = 13<BR>\n" );
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document.write( "Step 1, get rid of fractions<BR>\n" );
document.write( "3x + 6y = 96  eqn 1 times 8<BR>\n" );
document.write( "x + 2y = 32 then divided by 3<BR>\n" );
document.write( "4x + 3y = 78 eqn 2 times 6<BR>\n" );
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document.write( "x + 2y = 32 Solve for x<BR>\n" );
document.write( "x = 32 - 2y<BR>\n" );
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document.write( "Sub for x into the other eqn<BR>\n" );
document.write( "4(32-2y) + 3y = 78<BR>\n" );
document.write( "128 - 8y + 3y = 78<BR>\n" );
document.write( "-5y = -40<BR>\n" );
document.write( "y = 8<BR>\n" );
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document.write( "x = 32 - 2y<BR>\n" );
document.write( "x = 32 - 2*8<BR>\n" );
document.write( "x = 16<BR>\n" );
document.write( "That's how. </SPAN>\n" );
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