document.write( "Question 188491: please help me solve this problem:\r
\n" ); document.write( "\n" ); document.write( "two consecutive positive integers have the property that one integer times twice the other equals 612. What is the sum of these two integers?\r
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Algebra.Com's Answer #141309 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
call the 1st integer n (i is too easily confused, imo)
\n" ); document.write( "The 2nd integer is n+1.
\n" ); document.write( "Twice this integer is 2n+2
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\n" ); document.write( "n*(2n+2) = 612
\n" ); document.write( "2n^2 + 2n = 612
\n" ); document.write( "n^2 + n = 306
\n" ); document.write( "n^2 + n - 306 = 0
\n" ); document.write( "(n+18)*(n-17) = 0
\n" ); document.write( "n = -18 (we're looking for positive integers, so ignore -18)
\n" ); document.write( "n = 17 That one works.
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\n" ); document.write( "The 2 integers are 17 & 18, so the sum is 35\r
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