document.write( "Question 188491:  please help me solve this problem:\r
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document.write( "two consecutive positive integers have the property that one integer times twice the other equals 612. What is the sum of these two integers?\r
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document.write( "thank you! \n" );
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| Algebra.Com's Answer #141309 by Alan3354(69443)     You can put this solution on YOUR website! call the 1st integer n (i is too easily confused, imo) \n" ); document.write( "The 2nd integer is n+1. \n" ); document.write( "Twice this integer is 2n+2 \n" ); document.write( "------------- \n" ); document.write( "n*(2n+2) = 612 \n" ); document.write( "2n^2 + 2n = 612 \n" ); document.write( "n^2 + n = 306 \n" ); document.write( "n^2 + n - 306 = 0 \n" ); document.write( "(n+18)*(n-17) = 0 \n" ); document.write( "n = -18 (we're looking for positive integers, so ignore -18) \n" ); document.write( "n = 17 That one works. \n" ); document.write( "------------- \n" ); document.write( "The 2 integers are 17 & 18, so the sum is 35\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |