document.write( "Question 188486: How many liters of a 20% alcohol solution and how many liters of a 50% alcohol solution must be mixed to produce 9 liters of a 30% alcohol solution? \n" ); document.write( "

Algebra.Com's Answer #141305 by Mathtut(3670) $\"\"$ $\"About$

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let x and y be the amounts of 20% and 50% solutions respectively
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\n" ); document.write( "x+y=9........eq 1
\n" ); document.write( ".2x+.5y=.3(9).eq 2
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\n" ); document.write( "rewrite eq 1 to x=9-y and plug this into eq 2
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\n" ); document.write( ".2(9-y)+.5y=2.7
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\n" ); document.write( "1.8-.2y+.5y=2.7
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\n" ); document.write( ".3y=.9
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\n" ); document.write( "y=3...liters of 50% solution
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\n" ); document.write( "x=9-y=9-3=6 liters of 20% solution \n" ); document.write( "

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