document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188470>Question 188470</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A farmer needs 120 gallons of an 18% nitrogen fertilizer. But the farmer only has 10% nitrogen and 22% nitrogen fertilizer. How much of each fertilizer does the farmer need to mix? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141289 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A farmer needs 120 gallons of an 18% nitrogen fertilizer. But the farmer only has 10% nitrogen and 22% nitrogen fertilizer. How much of each fertilizer does the farmer need to mix?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "nitro + nitro = nitro<BR>\n" );
document.write( "0.10x + 0.0.22(120-x) = 0.18*120<BR>\n" );
document.write( "--------------------------------<BR>\n" );
document.write( "Multiply thru by 100 to get:<BR>\n" );
document.write( "10x + 22*120 - 22x = 18*120<BR>\n" );
document.write( "-12x = -4*120<BR>\n" );
document.write( "x = 40 gallons (amt. of 10% solution needed )<BR>\n" );
document.write( "120-x = 80 gallons (amt. of 22% solution needed)<BR>\n" );
document.write( "=================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );