document.write( "Question 188381: perimeter of a recatnagle is 200cm. area of the rectangle is 2491 square cm. what is the size of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #141239 by uday1435(57)\"\" \"About 
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P = 200 = 2(L + w ) Dividing by 2 we have (L + w) = 100 ……. Eqn(1)
\n" ); document.write( "Area = Lw = 2491 sq.cms
\n" ); document.write( "(L – w)^2 = (L + w)^2 – 4Lw pluging in the values of (L+w) and Lw we get
\n" ); document.write( "(L – w)^2 = 100^2 – 4(2491) = 100000 – 9964 = 36
\n" ); document.write( "Taking square roots (L – w) = 6 ……………. ... Eqn(2)
\n" ); document.write( "We have (L + w) = 100 ……………. Eqn(1)
\n" ); document.write( "Adding Eqn(1) and Eqn(2) 2L = 106
\n" ); document.write( "Dividing by 2 we get L = 106/2 = 53
\n" ); document.write( "Substituting in Eq(1) 53 + w = 100, so w = 100 – 53 = 47
\n" ); document.write( "Answer: Length = 53 cms and Width = 47 cms\r
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\n" ); document.write( "\n" ); document.write( "If you still require further clarifications please write to
\n" ); document.write( "udayakumar.t.r@gmail.com
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