document.write( "Question 188378: Perimeter of a rectangle is 200cm. The Area of the Rectangle is 2491 square cm. what is the size of the rectangle?
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Algebra.Com's Answer #141222 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "P=2L+2W= 200cm, eqn1 \n" ); document.write( "A=L*W= 2491 sq.cm., eqn2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In eqn 2 we get, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Substitute eqn 3 in eqn 1: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "By Quadratic, where \n" ); document.write( "Discriminant: \n" ); document.write( "Then, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "For Width you got 2 values, W1=53cm; W2=47cm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "For Length: Via eqn 3, \n" ); document.write( " \n" ); document.write( "L1=47cm; L2=53cm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Check on Perimeter: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "We use L2 & W2 on Area: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, Rectangle can be of L1 & W1 or L2 & W2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " |