document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188311>Question 188311</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the length of fence required to enclose a rectangular field is 300 meters.  What are the dimensions of the field if it is known that hte difference between its lenght and width is 50 meters </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141220 by </B><A HREF=/tutors/aboutme.mpl?userid=uday1435><B>uday1435(57)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=uday1435><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=uday1435><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141220\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter p = 2(l+w) = 300, Dividing by 2 we have  l + w = 150 .......Eq.1<BR>\n" );
document.write( "and  l – w = 50 ..................................................... Eq.2<BR>\n" );
document.write( "Adding  Eq.1 and Eq.2 we get<BR>\n" );
document.write( "2l = 200. , Dividing both sides by 2 we get  l = 100<BR>\n" );
document.write( "Since l + w = 150  w = 150 – 100 = 50<BR>\n" );
document.write( "The answer is Length = 100 meters and width = 50 meters\r<BR>\n" );
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