document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188371>Question 188371</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618503080/algebrahomeworkh>An Applied Approach</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Two investments earn an annual income of $575. One investment earns an annual simple interest rate of 8.5%, and the other investment earns an annual simple interest rate of 6.4%. The total amount invested is $8,000. How much is invested in each account? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141219 by </B><A HREF=/tutors/aboutme.mpl?userid=Mathtut><B>Mathtut(3670)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Mathtut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x and y be the amount invested at 8.5% and 6.4 % respectively<BR>\n" );
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document.write( "x+y=8000............eq 1<BR>\n" );
document.write( ".085x+.064y=575.....eq 2<BR>\n" );
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document.write( "rewrite eq 1 to x=8000-y and plug it into eq 2<BR>\n" );
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document.write( ".085(8000-y)+.064y=575<BR>\n" );
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document.write( "680-.085y+.064y=575<BR>\n" );
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document.write( "-.021y=-105<BR>\n" );
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document.write( "y=5000 invested at 6.4%<BR>\n" );
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document.write( "x=8000-5000=3000 invested at 8.5% </SPAN>\n" );
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