document.write( "Question 188337: 87% of all A's are B's. 3% of all B's are A's. There are 13 A's that are NOT B's. How many B's are not A's? PLEASE HELP! I AM STUCK! THANK YOU! \n" ); document.write( "
Algebra.Com's Answer #141215 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If 87% of As are Bs, then 13% of As are NOT Bs. (100% - 87% = 13%). If 13% of As are not Bs, and there are 13 As that are not Bs:\r
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\n" ); document.write( "\n" ); document.write( "Therefore, there are 0.87 times 100 = 87 As that are Bs. And if .03Bs are As, then:\r
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\n" ); document.write( "\n" ); document.write( "Since 3% of Bs are As, 97% of Bs are NOT As, so:\r
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