document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188363>Question 188363</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this question, I'll give the exact question.\r<BR>\n" );
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document.write( "Question: Given that both rational expressions are defined, what is the value of K: 6x^2-5x-4     2x+1<BR>\n" );
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document.write( "     3x^2+kx+20     x-5  \r<BR>\n" );
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document.write( "If the equation re-arranged itself, here what it is: (6x^2-5x-4)over (3x^2+kx+20) is equal to (2x+1) over (x-5)\r<BR>\n" );
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document.write( "here's my process, I'm stuck.\r<BR>\n" );
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document.write( "QUESTION:(6x^2-5x-4)/(3x^2+kx+20) = (2x+1)/(x-5)<BR>\n" );
document.write( "6*-4=-24 Find 2 numbers that multiply to -24 and add to -5<BR>\n" );
document.write( "(x-8)(x+3) Divide both terms by 6<BR>\n" );
document.write( "(x-8/6)(x+3/6) Simplify and do \"bottom's up\"<BR>\n" );
document.write( "(3x-4)(2x+1)/(3x^2+kx+20) = (2x+1)/(x-5) And that's as far as I got.\r<BR>\n" );
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document.write( "The answer the teacher gave me was k=19, i would like it very much if someone showed me a step by step </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141205 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141205\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> QUESTION:<BR>\n" );
document.write( "(6x^2-5x-4)/(3x^2+kx+20) = (2x+1)/(x-5)<BR>\n" );
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document.write( "(2x+1)(3x-4)/(3x^2+kx+20) = (2x+1)/(x-5)<BR>\n" );
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document.write( "Divide both sides by (2x+1) to get:<BR>\n" );
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document.write( "(3x-4)/(3x^2+kx+20) = 1/(x-5)\r<BR>\n" );
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document.write( "----<BR>\n" );
document.write( "Cross-multiply to get:<BR>\n" );
document.write( "(3x-4)(x-5) = 3x^2+kx+20<BR>\n" );
document.write( "----<BR>\n" );
document.write( "3x^2 -19x + 20 = 3x^2 + kx + 20<BR>\n" );
document.write( "---<BR>\n" );
document.write( "-19x = kx<BR>\n" );
document.write( "--<BR>\n" );
document.write( "k = -19<BR>\n" );
document.write( "====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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