document.write( "Question 188346This question is from textbook
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document.write( ": Charlotte's time to travel 250 miles is 1 hour more than Lorraine's time to travel 180 miles. Charlotte drove 5 miles per hour faster than Lorraine. How fast did each one travel.\r
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document.write( "thanks,
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document.write( "I know this problem involves the quadratic equation and I know there will be two different possible scenarios. I just need help seting up the equation. \n" );
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Algebra.Com's Answer #141204 by dukesmart(20) ![]() You can put this solution on YOUR website! Let x= the speed of Charlotte travel \n" ); document.write( "Let y= the speed of Lorraine travel \n" ); document.write( "We can establish equations as follows:\r \n" ); document.write( "\n" ); document.write( "(250/x) - 1 = 180/y ......(1)\r \n" ); document.write( "\n" ); document.write( "x - 5 = y ..........(2)\r \n" ); document.write( "\n" ); document.write( "(1) can be written : (250/x) -1 = 180/(x - 5)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "or (250 - x)/x = 180/(x-5) \n" ); document.write( " (250-x)(x-5) = 180x \n" ); document.write( " 250x-1250-x^2+5x = 180x \n" ); document.write( " -x^2+250x+5x-180x-1250 = 0 \n" ); document.write( " x^2-75x+1250 = 0 \n" ); document.write( "x1 =[75+sqrt(75^2-4(1250)]/2= [75+ sqrt(625)]/2= 50 \n" ); document.write( "x2= [75-sqrt(625)]/2=25\r \n" ); document.write( "\n" ); document.write( "two solutions if x=50 miles/hour then y= 45 miles/hour \n" ); document.write( " x=25 miles /hour then y=20 miles/hour \n" ); document.write( " |