document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3225>Question 3225</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hey i would really really really appreciate some help, test tomorrow!<BR>\n" );
document.write( "(e^t - e^-t )/ 3 =2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1412 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  (e^t - e^-t )/ 3 =2<BR>\n" );
document.write( " Let u = e^t, we have e^-t = 1/u,<BR>\n" );
document.write( " so (u - 1/u)/3 = 2, <BR>\n" );
document.write( " Cancelling the denominator by multiply 3u,<BR>\n" );
document.write( " u^2 - 1 = 6u or <BR>\n" );
document.write( " u^2 -6u - 1 = 0,<BR>\n" );
document.write( " By quadratic formula<BR>\n" );
document.write( " u = 3 + sqrt(10) or  3 - sqrt(10)(negative ,invalid)<BR>\n" );
document.write( " <BR>\n" );
document.write( " Since u = e^t = 3 + sqrt(10), so t = ln [3 + sqrt(10)]...Answer\r<BR>\n" );
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document.write( " Check, t = ln 3, e^t =  3 + sqrt(10),<BR>\n" );
document.write( " e^t =  -3 + sqrt(10) <BR>\n" );
document.write( " (e^t - e^-t )/ 3 = (3 - (-3))/3 = 2..correct\r<BR>\n" );
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document.write( " Kenny </SPAN>\n" );
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