document.write( "Question 26256: There are 850 douglas fir and ponderosa pine trees in a section of forest bought by sawz logging co. The company paid a average of $300 for each douglas fir and $225 for each ponderosa pine. if the company paid $217500 for the trees, how many of each kind did the company buy. I wasnt sure at all how to get this one started. i am not sure if which number i am trying break down.
\n" ); document.write( "300x+225x-850=217,500. that doesnt make logical sense to me. i know it will 300x and 225x. I am not sure where to go from there.
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Algebra.Com's Answer #14119 by Paul(988)\"\" \"About 
You can put this solution on YOUR website!
Let D. Trees be x
\n" ); document.write( "Let P, trees be y
\n" ); document.write( "Now; together they equal 850 trees
\n" ); document.write( "so: x+y=850 (solve for y)
\n" ); document.write( "y=850-x (subsitution)
\n" ); document.write( "D. trees cost $300 and P. trees cost $225
\n" ); document.write( "together there cost equal $217500 that includes the amount of tree they buy..
\n" ); document.write( "Now the amount are unknown so the equation is.
\n" ); document.write( "300x+225y=217500 (subsitue for y)
\n" ); document.write( "300x+225(850-x)=217500
\n" ); document.write( "300x-225x+191250=217500
\n" ); document.write( "75x=26250
\n" ); document.write( "x=350
\n" ); document.write( "y=850-350
\n" ); document.write( "y=500.\r
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\n" ); document.write( "\n" ); document.write( "Hence, there were 350 D. trees bought, and 500 P. trees bought.
\n" ); document.write( "Paul.
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