document.write( "Question 188304: The length of a rectangular graden is 5ft longer than its width. The garden is surrounded by a 2-foot-wide sidewalk. The sidewalk has an area of 76 sq ft. Find the dimensions of the garden. \n" ); document.write( "
Algebra.Com's Answer #141170 by solver91311(24713)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "If the sidewalk is 2 ft wide all the way around, then the rectangle defined by the outer edge of the sidewalk is 4 feet longer and 4 feet wider than the garden. So let the width of the garden be x and then the length of the garden is x + 5, so the area of the garden is:\r
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\n" ); document.write( "\n" ); document.write( "And the area of the rectangle defined by the outer edge of the sidewalk is:\r
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\n" ); document.write( "\n" ); document.write( "And the difference between the two is 76 square feet, so:\r
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\n" ); document.write( "\n" ); document.write( "Solve for x:\r
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\n" ); document.write( "\n" ); document.write( "So the width of the garden is 5 feet, the length is 10 feet.\r
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\n" ); document.write( "\n" ); document.write( "Answer checks.\r
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