document.write( "Question 188320This question is from textbook
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\n" ); document.write( "|1 2 3| =4\r
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\n" ); document.write( "\n" ); document.write( "|x y z|
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\n" ); document.write( "|2 4 6|
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Algebra.Com's Answer #141161 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Remember, you can multiply a scalar value \"k\" by any row of a determinant like this:\r
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\n" ); document.write( "\n" ); document.write( " Note: you can pick any row. In this example, I'm using the first row.\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28matrix%283%2C3%2Cx%2Cy%2Cz%2Cu%2Cv%2Cw%2C1%2C2%2C3%29%29=4\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "Since the bottom row of the resulting determinant is 2, 4, and 6 this means that this row is 2 times the bottom row of the given determinant.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2Aabs%28matrix%283%2C3%2Cx%2Cy%2Cz%2Cu%2Cv%2Cw%2C1%2C2%2C3%29%29=2%2A4\" Multiply both sides by 2\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28matrix%283%2C3%2Cx%2Cy%2Cz%2Cu%2Cv%2Cw%2C2%2A1%2C2%2A2%2C2%2A3%29%29=2%2A4\" Multiply the scalar 2 by the entire bottom row of the determinant\r
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\n" ); document.write( "\n" ); document.write( "\"abs%28matrix%283%2C3%2Cx%2Cy%2Cz%2Cu%2Cv%2Cw%2C2%2C4%2C6%29%29=8\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"abs%28matrix%283%2C3%2Cx%2Cy%2Cz%2Cu%2Cv%2Cw%2C2%2C4%2C6%29%29=8\"
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