document.write( "Question 188287: let f(x) = cos x. Prove that...
\n" ); document.write( "[f(x+h) - f(x)]/h = cosx[(cosh-1)/h]- sinx[sinh/h]
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Algebra.Com's Answer #141137 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Note: \"cos%28x%2Bh%29=cos%28x%29cos%28h%29-sin%28x%29sin%28h%29\" this is one of the many trig identities\r
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\n" ); document.write( "\n" ); document.write( "Since \"f%28x%29+=+cos%28x%29\", this means that \"f%28x%2Bh%29=cos%28x%2Bh%29=cos%28x%29cos%28h%29-sin%28x%29sin%28h%29\" or simply \"f%28x%2Bh%29=cos%28x%29cos%28h%29-sin%28x%29sin%28h%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28f%28x%2Bh%29-f%28x%29%29%2Fh\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28%28+cos%28x%29cos%28h%29-sin%28x%29sin%28h%29+%29-+cos%28x%29%29%2Fh\" Plug in \"f%28x%29+=+cos%28x%29\" and \"f%28x%2Bh%29=cos%28x%29cos%28h%29-sin%28x%29sin%28h%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28cos%28x%29cos%28h%29+-+cos%28x%29+-sin%28x%29sin%28h%29+%29%2Fh+\" Remove the parenthesis and rearrange the terms (I just moved the last cosine term right after the first term)\r
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\n" ); document.write( "\n" ); document.write( "\"%28cos%28x%29+%28cos%28h%29+-+1%29+-sin%28x%29sin%28h%29%29%2Fh\" Factor the term \"cos%28x%29\" from the first two terms.\r
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\n" ); document.write( "\n" ); document.write( "\"%28cos%28x%29+%28cos%28h%29+-+1%29%29%2Fh+-%28sin%28x%29sin%28h%29%29%2Fh\" Break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "So where \"f%28x%29=cos%28x%29\"\r
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\n" ); document.write( "\n" ); document.write( "Note: if you are in Calculus, then this would show that the derivative of \"cos%28x%29\" is \"-sin%28x%29\" (with a few more steps).
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