document.write( "Question 188257This question is from textbook Applied Statistics in Business and Economics
\n" ); document.write( ": Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86. \r
\n" ); document.write( "\n" ); document.write( "(a) Construct a 90 percent confidence interval for the proportion of all kernels that would not pop.
\n" ); document.write( "(b) Check the normality assumption.
\n" ); document.write( "(c) Try the Very Quick Rule. Does it work well here? Why, or why not?
\n" ); document.write( "(d) Why might this sample not be typical?
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Algebra.Com's Answer #141134 by stanbon(75887)\"\" \"About 
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Biting an unpopped kernel of popcorn hurts!
\n" ); document.write( "As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86.
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\n" ); document.write( "(a) Construct a 90 percent confidence interval for the proportion of all kernels that would not pop.
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\n" ); document.write( "sample mean = 86/773 = 0.1113
\n" ); document.write( "E = 1.645*sqrt[0.1113*0.8887/773] = 0.0186
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\n" ); document.write( "90% C.I.: 0.1113-0.0186 < p < 0.1113+0.0186
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\n" ); document.write( "(b) Check the normality assumption.
\n" ); document.write( "I'll leave that to you
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\n" ); document.write( "(c) Try the Very Quick Rule. Does it work well here? Why, or why not?
\n" ); document.write( "I'm not sure what the Quick Rule is.
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\n" ); document.write( "(d) Why might this sample not be typical?
\n" ); document.write( "It's only one person's bag of popcorn.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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