document.write( "Question 188263: One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______\r
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document.write( "I am stumped. Thank you! Jessica \n" );
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Algebra.Com's Answer #141124 by Alan3354(69443) You can put this solution on YOUR website! One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______ \n" ); document.write( "--------------------- \n" ); document.write( "age of 1st coin = y (number of years) \n" ); document.write( "age of 2nd coin = y+2 \n" ); document.write( "------- \n" ); document.write( "In 3 years: \n" ); document.write( "(y+3)*(y+5) = 35 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(y + 10)*(y - 2) = 0 \n" ); document.write( "y = 2 years (ignore the -10) \n" ); document.write( "2nd coin is 4 years old\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |