document.write( "Question 188263: One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______\r
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Algebra.Com's Answer #141124 by Alan3354(69443)\"\" \"About 
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One coin is 2 years older than another. In 3 years, the product of their ages will be 35. Find the present ages of the coins. _______ and _______
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\n" ); document.write( "age of 1st coin = y (number of years)
\n" ); document.write( "age of 2nd coin = y+2
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\n" ); document.write( "In 3 years:
\n" ); document.write( "(y+3)*(y+5) = 35
\n" ); document.write( "\"y%5E2+%2B+8y+%2B+15+=+35\"
\n" ); document.write( "\"y%5E2+%2B+8y+-+20+=+0\"
\n" ); document.write( "(y + 10)*(y - 2) = 0
\n" ); document.write( "y = 2 years (ignore the -10)
\n" ); document.write( "2nd coin is 4 years old\r
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