document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188189>Question 188189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A man walks at a pace of 3 miles per hour. After 2 hours he stops for a rest. Let t be time AFTER the rest when he continues on his walk. Let d be the TOTAL distance traveled since he started. Write an equation linking d and t.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141098 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141098\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r<BR>\n" );
document.write( "\n" );
document.write( "Distance travelled before the rest=3*2=6 mi<BR>\n" );
document.write( "Distance travelled after the rest=3t<BR>\n" );
document.write( "So, total distance (d)=dist before the rest+distance after the rest or<BR>\n" );
document.write( "d=6+3t----------------------ans\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );