document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188181>Question 188181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> can you please help me :\r<BR>\n" );
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document.write( "convert this linear equation to standard form?\r<BR>\n" );
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document.write( "y=1/2x-2/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141050 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = 1/2x - 2/3<BR>\n" );
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document.write( "Get rid of the fractions, multiply both sides by 6<BR>\n" );
document.write( "6y = 3x - 4<BR>\n" );
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document.write( "Subtract 3x from both sides, results<BR>\n" );
document.write( "-3x + 6y = -4<BR>\n" );
document.write( "Multiply equation by -1  to change the signs<BR>\n" );
document.write( "3x - 6y = 4 </SPAN>\n" );
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