document.write( "Question 26238: I am very frustrated. I am working on geometric series of numbers and thought that it would be easy but, I have not done this in a while and I have to admit that I am perplexed. Here is what I must solve:\r
\n" ); document.write( "\n" ); document.write( "Use the geometric series of numbers 1, 2, 4, 8,...to find the following:
\n" ); document.write( "a) What is r, the ratio between 2 consecutive terms?
\n" ); document.write( " (I got r=1)
\n" ); document.write( "b) Using the formula for the nth term of a geometric series, what it the 24th term?\r
\n" ); document.write( "\n" ); document.write( "c) Using the formula for the sum of a geometric series, what is the sum of the first 10 terms?\r
\n" ); document.write( "\n" ); document.write( "Could you please help refresh my memory by showing me step by step how to complete this first set of problems? Thank you!!!!
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Algebra.Com's Answer #14104 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
r=2/1 or 4/2 or 8/4; at any rate r=2
\n" ); document.write( "Formula for nth term: nth term=(1st term)(r^(n-1))
\n" ); document.write( "24th term=(1)(2^(23))=8388608
\n" ); document.write( "Formula for sum: Sum of n terms =(1st term)[1-r^n]/[1-r]
\n" ); document.write( "Sum of 10 terms =1[1-2^10]/[1-2]
\n" ); document.write( " = -1023/(-1)=1023\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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