document.write( "Question 188148This question is from textbook algebra2
\n" ); document.write( ": One factor of x^3+x^2-14x-24 is (x-4).
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Algebra.Com's Answer #141026 by jim_thompson5910(35256) $\"\"$ $\"About$

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Since (x-4) is a factor, this means that x=4 is a root (or zero) of $\"x%5E3%2Bx%5E2-14x-24\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now set up a synthetic division table by placing the zero 4 and the coefficients of $\"x%5E3%2Bx%5E2-14x-24\"$ along the top row. Perform synthetic division to get:\r
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document.write( " 4 |1   1   -14   -24\r\n" );
document.write( "   |    4    20    24\r\n" );
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document.write( "    1   5     6     0\r\n" );
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\n" ); document.write( "\n" ); document.write( "Since the remainder is 0, this means that 4 is a root.\r
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\n" ); document.write( "\n" ); document.write( "The first three numbers in the bottom row form the quadratic: $\"x%5E2%2B5x%2B6\"$ \r
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\n" ); document.write( "\n" ); document.write( "Now solve $\"x%5E2%2B5x%2B6=0\"$ to find the other 2 solutions. \n" ); document.write( "

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