document.write( "Question 188107: MR. Ramirez sells blue grass seed for $3.50 per pound and a fescue seed for $1.70 per pound. He wishes to make a 50 - pound mixture to sell for $2.96 per pound. Find how much of each kind of seed he nust use in the mixture \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "Let x = the number of pounds of bluegrass seed
\n" );
document.write( "let y=the number of fescue seed \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "x + y= 50 \r
\n" );
document.write( "\n" );
document.write( "3.50 x + 1.70y= 2.96(50)\r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "x +y =50
\n" );
document.write( "-3.50 -3.50y = -175
\n" );
document.write( " 3.50 + 1.70y= 148
\n" );
document.write( "------------------------
\n" );
document.write( " -1.80y= -27 y=? \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "x+ ? =50 \r
\n" );
document.write( "\n" );
document.write( "x=35 need a full break down of how my book got 35 i fell short from doing the problem
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #141002 by Mathtut(3670) ![]() You can put this solution on YOUR website! let x and y be the number of pounds of blue grass and fescue respectively \n" ); document.write( ": \n" ); document.write( "x+y=50......eq 1 \n" ); document.write( "3.50x+1.7y=2.96(50)...eq 2 \n" ); document.write( ": \n" ); document.write( "rewrite eq 1 to x=50-y and x's value of 50-y into eq 2 for all occurrences of x \n" ); document.write( ": \n" ); document.write( "3.5(50-y)+1.7y=148 \n" ); document.write( ": \n" ); document.write( "175-3.5y+1.7y=148 \n" ); document.write( ": \n" ); document.write( "-1.8y=-27 \n" ); document.write( ": \n" ); document.write( "y=15 pounds \n" ); document.write( ": \n" ); document.write( "x=50-y=50-15=35 pounds \n" ); document.write( " |