document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188107>Question 188107</A>: <I><SPAN STYLE=\"word-break: break-all;\"> MR. Ramirez sells blue grass seed for $3.50 per pound and a fescue seed for $1.70 per pound. He wishes to make a 50 - pound mixture to sell for $2.96 per pound. Find how much of each kind of seed he nust use in the mixture \r<BR>\n" );
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document.write( "Let x = the number of pounds  of bluegrass seed<BR>\n" );
document.write( "let y=the number of fescue seed \r<BR>\n" );
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document.write( "x + y= 50 \r<BR>\n" );
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document.write( "3.50 x + 1.70y= 2.96(50)\r<BR>\n" );
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document.write( "x +y =50<BR>\n" );
document.write( "-3.50  -3.50y = -175<BR>\n" );
document.write( " 3.50  + 1.70y=  148<BR>\n" );
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document.write( "        -1.80y=  -27          y=? \r<BR>\n" );
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document.write( "x+ ? =50  \r<BR>\n" );
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document.write( "x=35 need a full break down of how my book got 35 i fell short from doing the problem <BR>\n" );
document.write( "                                              </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #141000 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=141000\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, you got off to a good start with:<BR>\n" );
document.write( "1) x+y = 50<BR>\n" );
document.write( "2) 3.50x+1.70y = 2.96(50)<BR>\n" );
document.write( "Now rewrite equation 1) as: x = 50-y and substitute this for x in equation 2).<BR>\n" );
document.write( "2a) 3.50(50-y)+1.70y = 2.96(50) Simplfy this.<BR>\n" );
document.write( "2b) 175-3.50y+1.70y = 148<BR>\n" );
document.write( "2c) 175-1.8y = 148 Subtract 175 from both sides.<BR>\n" );
document.write( "-1.8y = -27 Divide both sides by -1.8<BR>\n" );
document.write( "y = 15 and...<BR>\n" );
document.write( "x = 50-y<BR>\n" );
document.write( "x = 50-15<BR>\n" );
document.write( "x = 35<BR>\n" );
document.write( "So, Mr. Ramirez needs to mix 35 lbs of Bluegrass seed @ $3.50 per lb. with 15 lbs of Fescue seed @ $1.70 per lb. to obtain 50 lbs of the mixture @ $2.96 per lb. </SPAN>\n" );
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