document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=188103>Question 188103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve the following equation? ln X + ln(x+3)= 1\r<BR>\n" );
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document.write( "Thanks for using your time to help me out. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140977 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve the following equation? ln X + ln(x+3)= 1 <BR>\n" );
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document.write( "Comment: These ln terms are exponents.<BR>\n" );
document.write( "When you are adding them you are multiplying.<BR>\n" );
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document.write( "ln(x(x+3)) = 1<BR>\n" );
document.write( "x(x+3) = e^1<BR>\n" );
document.write( "x^2 + 3x - e = 0<BR>\n" );
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document.write( "Note: e = 2.71828....<BR>\n" );
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document.write( "Use the quadratic formula to solve for \"x\":<BR>\n" );
document.write( "x = [-3 +- sqrt(9 - 4*1*-e)]/2\r<BR>\n" );
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document.write( "x = [-3 +- sqrt(9+4e)]/2\r<BR>\n" );
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document.write( "x = [-3 +- 4.4579]/2<BR>\n" );
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document.write( "Positive solution:<BR>\n" );
document.write( "x = 0.7290..<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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