document.write( "Question 188051: A total of $27,000 was invested, part at 10%and part at 12%. The total yield(total interest) was $2990. How much money was investedat each rate? \n" ); document.write( "

Algebra.Com's Answer #140958 by solver91311(24713) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Let x represent the amount invested at 12%. So the amount of interest earned on that part of the investment was 0.12x. The rest of the money, or 27,000 - x is the amount invested at 10%, so the amount of interest earned on that part of the investment was 0.10(27,000 - x). And these two amounts of interest add up to $2,990.\r
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\n" ); document.write( "\n" ); document.write( "Solve for x to get one amount, subtract that value from 27000 to get the other.\r
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