document.write( "Question 188003: CAN ANYONE HELP WITH THIS PROBLEM ... I AM SO STUCK!! THANKS\r
\n" ); document.write( "\n" ); document.write( "Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute. There are 700 liters in the pond to start.\r
\n" ); document.write( "\n" ); document.write( "Let W represent the amount of water in the pond (in liters), and let T represent the number of minutes that water has been added. Write an equation relating W to T, and then graph your equation using the axes below.
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Algebra.Com's Answer #140930 by ankor@dixie-net.com(22740)\"\" \"About 
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Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute. There are 700 liters in the pond to start.
\n" ); document.write( "Let W represent the amount of water in the pond (in liters), and let T represent the number of minutes that water has been added. Write an equation relating W to T, and then graph your equation using the axes below.
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\n" ); document.write( "the equation would be: Total water (W) = 35L*minutes(T) + 700L
\n" ); document.write( "W = 35T + 700
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\n" ); document.write( "Put T on the horizontal (x) and W on the vertical (Y)
\n" ); document.write( "Graph should look like this:
\n" ); document.write( "\"+graph%28+300%2C+200%2C+-20%2C+60%2C+-500%2C+3000%2C+35x%2B700%29+\"
\n" ); document.write( "Note when T = 0, you have 700L, when T = 60, you have 35(60)+ 700 = 2800L
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