document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26222>Question 26222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!<BR>\n" );
document.write( "I would like to know if you can help me with the following problem.\r<BR>\n" );
document.write( "\n" );
document.write( "Three kinds of coffee are to be mixed to get a blend.  One kind costs $0.40 per pound, the second $0.80 per pound and the third $1.00 per pound.  110 pounds of the mix is wanted and it should cost $0.60 per pound.  The amount of coffee costing $0.80 per pound should be 2/3 of the amount at $0.40 per pound.  How much of each kind of coffee should be used?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14092 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14092\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let amount of 40 cent coffee be \"x\"<BR>\n" );
document.write( "The amount of 80 cent coffee is (2/3)x<BR>\n" );
document.write( "And amount of 100 cent coffee is (110-x-(2/3)x)=(110-(5/3)x)<BR>\n" );
document.write( "Value of 40 cent coffee is 40x<BR>\n" );
document.write( "Value of 80 cent coffee is 80(2/3)x<BR>\n" );
document.write( "Value of 100cent coffee is 100(110-(5/3)x)<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "Value of 40 + Value of 80 + Value of 100=60(110)cents<BR>\n" );
document.write( "   40x+80(2/3)x+100(110-(5/3)x)=60(110) cents<BR>\n" );
document.write( "   2x+4(2/3)x+5(110x)-(5/3))x=3(110) cents<BR>\n" );
document.write( "   6x+8x+1650-25x=990<BR>\n" );
document.write( "             -11x=-660<BR>\n" );
document.write( "                x=60 lbs. of 40cent coffee<BR>\n" );
document.write( "            (2/3)x=40 lb. of 80cent coffee<BR>\n" );
document.write( "          110-(5/3)x=110-(5/3)(60)=10 lbs. of $1.00 coffee<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );