document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187981>Question 187981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a balloon is ascending at 3 feet per second and another balloon is descending from 756 feet at 4 feet per second, at how many seconds will they meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140918 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140918\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a balloon is ascending at 3 feet per second and another balloon is descending from 756 feet at 4 feet per second, at how many seconds will they meet?<BR>\n" );
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document.write( "It's very unlikely they will meet, due to air currents.<BR>\n" );
document.write( "Ignoring that, we can find when they'll be at the same altitude.<BR>\n" );
document.write( "The faster balloon is gaining on the other one at the difference in speed, 4-3 = 1 ft/sec.<BR>\n" );
document.write( "756/1 = 756 seconds.<BR>\n" );
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