document.write( "Question 187863This question is from textbook algebra structure and methoed
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\n" ); document.write( "\n" ); document.write( "ramon cna do the weekly billing in 2 hrs luann needs three hours. if roman works for 30 minute and then is joined by luann, how long will it take them to finish\r
\n" ); document.write( "\n" ); document.write( "the tens digit of a two digit number is one more than 3 times the unit digit.
\n" ); document.write( "subtracting 45 from the number reverses it , find the original number\r
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Algebra.Com's Answer #140898 by ankor@dixie-net.com(22740)\"\" \"About 
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Ramon can do the weekly billing in 2 hrs; Luann needs three hours. If Romon
\n" ); document.write( " works for 30 minutes, and then is joined by Luann, how long will it take them
\n" ); document.write( " to finish?
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\n" ); document.write( "Let t = amt of time required for them to finish
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\n" ); document.write( "Change 30 min to .5 hrs
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\n" ); document.write( "Let the completed job = 1
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\n" ); document.write( "\"%28t%2B.5%29%2F2\" + \"t%2F3\" = 1
\n" ); document.write( "Multiply equation by 6 to get rid of denominators, results:
\n" ); document.write( "3(t+.5) + 2t = 6
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\n" ); document.write( "3t + 1.5 + 2t = 6
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\n" ); document.write( "5t = 6 - 1.5
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\n" ); document.write( "5t = 4.5
\n" ); document.write( "t = \"4.5%2F5\"
\n" ); document.write( "t = .9 hrs which is .9(60) = 54 min to finish the job
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\n" ); document.write( "Check solution:
\n" ); document.write( "\"%28.9%2B.5%29%2F2\" + \".9%2F3\" =
\n" ); document.write( "\"1.4%2F2\" + \".9%2F3\" =
\n" ); document.write( ".7 + .3 = 1
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\n" ); document.write( "the tens digit of a two digit number is one more than 3 times the unit digit.
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\n" ); document.write( "Let x = the 10's digit, and let y = units
\n" ); document.write( "then
\n" ); document.write( "10x + y = the two digit number
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\n" ); document.write( "Write an equation for the statement:
\n" ); document.write( "\"the tens digit of a two digit number is one more than 3 times the unit digit.\"
\n" ); document.write( "x = 3y + 1
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\n" ); document.write( "subtracting 45 from the number reverses it ,
\n" ); document.write( "10x + y - 45 = 10y + x
\n" ); document.write( "10x - x = 10y - y + 45
\n" ); document.write( "9x = 9y + 45
\n" ); document.write( "Simplify, divide equation by 9
\n" ); document.write( "x = y + 5
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\n" ); document.write( " find the original number
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\n" ); document.write( "Substitute (3y+1) for x in the above equation
\n" ); document.write( "3y + 1 = y + 5
\n" ); document.write( "3y - y = 5 - 1
\n" ); document.write( "2y = 4
\n" ); document.write( "y = 2
\n" ); document.write( "then
\n" ); document.write( "x = 2 + 5
\n" ); document.write( "x = 7
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\n" ); document.write( "72 is our number
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\n" ); document.write( "Check solution in the statement:\"subtracting 45 from the number reverses it\"
\n" ); document.write( "72 - 45 = 27
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