document.write( "Question 187879: log base 3 (x) = log base 3 (1/x)+4\r
\n" ); document.write( "\n" ); document.write( "i understand that log base 3 (1/x) is subtracted so the problem could look something like this log base 3 (x) -log base 3 (1/x)=4\r
\n" ); document.write( "\n" ); document.write( "have one question doesnt 1 and x become log base 3 (1)- log base 3 (x)\r
\n" ); document.write( "\n" ); document.write( "the answer is 9, -9 but i dont know how to set up the problem i am stuck
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Algebra.Com's Answer #140884 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "9 certainly could be (and is) the value of x that makes this equation a true statement, but -9 cannot be. The domain of the log function is:\r
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\n" ); document.write( "\n" ); document.write( "So if you were to say:\r
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\n" ); document.write( "\n" ); document.write( "What you would really be saying is: \"Some undefined thing is equal to some other undefined thing plus 4.\" A patently absurd thing to say by any measure.\r
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\n" ); document.write( "\n" ); document.write( "Having said all of that, here's how to do the problem correctly:\r
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\n" ); document.write( "\n" ); document.write( "Now, use \"The log of the quotient is the difference of the logs\"\r
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\n" ); document.write( "\n" ); document.write( "Remove the parentheses and use to write:\r
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\n" ); document.write( "\n" ); document.write( "Since: \r
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\n" ); document.write( "\n" ); document.write( "Where whomever gave you the answer of -9 may have gone wrong is they might have said:\r
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\n" ); document.write( "\n" ); document.write( "And the roots of are 9 and -9, but you still have to go back to the original equation and consider any domain restrictions. Therefore, you must exclude the negative root.\r
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