document.write( "Question 26213: okay... welcome to my nightmear!
\n" ); document.write( "The perimeter of a triangle is 33 centimeters. The first side is 5 cetimeters shorter than the second, and the third is twice the first. Find the lengths of the sides...
\n" ); document.write( "I have a hard new class that I just entered and I'm not caught up yet. I've gotten as much help as I could, and this problem is the basis of the rest of my homework so if I could get this answer than I could probably figure the rest out. If you could show me the steps of the problem so that I can follow it... I would be eternally greatfull!
\n" ); document.write( "thank you :-p \n" ); document.write( "
Algebra.Com's Answer #14088 by longjonsilver(2297)\"\" \"About 
You can put this solution on YOUR website!
easy :-)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Let second side be x
\n" ); document.write( "then first is x-5
\n" ); document.write( "and third is 2(x-5)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "perimeter is (x-5) + x + 2(x-5) = 33
\n" ); document.write( "--> x - 5 + x + 2x - 10 = 33
\n" ); document.write( "4x - 15 = 33
\n" ); document.write( "4x = 48
\n" ); document.write( "x = 48/4
\n" ); document.write( "x = 12cm\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "So, first side is 7cm
\n" ); document.write( "second is 12cm
\n" ); document.write( "third is 14cm\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "-->check: these 3 add to give? 33cm, the perimeter, so correct!\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "jon.
\n" ); document.write( " \n" ); document.write( "
\n" );