document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187865>Question 187865</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0072451076/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> a person wishes to invest $2400.00 , part at 9% and persent at 6%. if the total interest desired at the end of the year is $189.00, how much should be invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140864 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140864\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .09X+.06(2,400-X)=189<BR>\n" );
document.write( ".09X+144-.06X=189<BR>\n" );
document.write( ".03X=189-144<BR>\n" );
document.write( ".03X=45<BR>\n" );
document.write( "X=45/.03<BR>\n" );
document.write( "X=$1,500 IS THE AMOUNT INVESTED @ 9%<BR>\n" );
document.write( "2,400-1,500=$900 IS THE AMOUNT INVESTED @6%.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( ".09*1,500+.06*900=189<BR>\n" );
document.write( "135+54=189<BR>\n" );
document.write( "189=189 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );