document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26215>Question 26215</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I've tried... believe me I have! ahhhhh! It seems so simple to most people, but this just wont go through my head! H-E-L-P please!<BR>\n" );
document.write( "Side A of a triangle is tice side B.  Side C is 2 meters shorter than side A.  The perimeter is 98 meters.  Help me find the length of each side please?<BR>\n" );
document.write( ":-D thanks times a bajillion! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14085 by </B><A HREF=/tutors/aboutme.mpl?userid=queenofit><B>queenofit(120)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=queenofit><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Ok first I will assume that when you said side A is tice side B, you meant twice, OK?.  You need to know several things to find this answer.  First, of course, you need the formula for the perimeter  which is side +side +side.  You have 3 sides.  We will call them side A B and C.  You know they equal 98 meters.  now, to find the sides.  First look at the question.  The only variable you would have that does not have a number involved is your B side.  So we will set up our equation as if we are solving for B, ok.  this is what you know from the equation<BR>\n" );
document.write( "B=B<BR>\n" );
document.write( "A= 2B  (side A is twice side B)<BR>\n" );
document.write( "C=2B-2  (side C is 2 meters shorter than side A, which is 2B)\r<BR>\n" );
document.write( "\n" );
document.write( "To get perimeter you add these three together and set them equal to 98\r<BR>\n" );
document.write( "\n" );
document.write( "2B + B + 2B - 2 = 98    (do you see how I set A + B + C = 98)<BR>\n" );
document.write( "5B-2=98  (combine like terms)<BR>\n" );
document.write( "5B=100    (solve using algebra)<BR>\n" );
document.write( "B=20    (side B = 20 meters)<BR>\n" );
document.write( "A= 2*20=40 (side A= 40 meters)<BR>\n" );
document.write( "C= 2*20-2=38 (side C = 38 meters)\r<BR>\n" );
document.write( "\n" );
document.write( "check by adding A + B + C = 98<BR>\n" );
document.write( "20+40+38=98\r<BR>\n" );
document.write( "\n" );
document.write( "I hope this helps, if you need further assistance, please let me know.<BR>\n" );
document.write( "A. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );