document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187800>Question 187800</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me with world problems i have no clue where to even begin, please help!! \r<BR>\n" );
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document.write( "An adjustable water sprinkler that sprays water in a circular pattern is placed at the center of a square field whose area is 1250 square feet. What is the shortest radius setting that can be used if all of the grass is to be watered?\r<BR>\n" );
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document.write( "thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140802 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An adjustable water sprinkler that sprays water in a circular pattern is placed at the center of a square field whose area is 1250 square feet. What is the shortest radius setting that can be used if all of the grass is to be watered?<BR>\n" );
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document.write( "We want to find the diagonal (d) of the square, that would be the diameter<BR>\n" );
document.write( " of the circular watered area. The radius would be half of that.<BR>\n" );
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document.write( "Since it's a square, the side dimensions would be:<BR>\n" );
document.write( "s = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%281250%29 ALIGN=MIDDLE  ALT=\"sqrt%281250%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "then we square that to find the hypotenuse: d^2 = s^2 + s^2, so we have:<BR>\n" );
document.write( "d^2 = 1250 + 1250<BR>\n" );
document.write( "d = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282500%29 ALIGN=MIDDLE  ALT=\"sqrt%282500%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "d = 50 ft<BR>\n" );
document.write( "then<BR>\n" );
document.write( "r = 25 ft is the minimum radius of the sprinkler<BR>\n" );
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