document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187795>Question 187795</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Help mark solve the following homework problem in geometry: two angles are complementary and one angle is 36 degrees more than twice the other.Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140797 by </B><A HREF=/tutors/aboutme.mpl?userid=mgmoeab><B>mgmoeab(37)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mgmoeab><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mgmoeab><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two angles are complementary.. that means their sum is equal to 90 degrees.<BR>\n" );
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document.write( "If you choose \"X\" to be one of the unknown angles, and you are told that one angle is 36 degrees more than twice the other, you can write this as:<BR>\n" );
document.write( " (36 + 2x) + x = 90<BR>\n" );
document.write( "  36 + (2x + x) = 90 (Group like terms)<BR>\n" );
document.write( "  36 + 3x = 90<BR>\n" );
document.write( "  3x = 90-36<BR>\n" );
document.write( "  3x = 54<BR>\n" );
document.write( "  x = 18  (This is your first angle)\r<BR>\n" );
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document.write( "If you subtract 90-18 = 72 (This is your second angle)<BR>\n" );
document.write( "Then the angles are 18 and 72!\r<BR>\n" );
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document.write( "Hope it helps! </SPAN>\n" );
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