document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187737>Question 187737</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of the circle with center (1,2) and tangent to x+y=1.\r<BR>\n" );
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document.write( "Thanks for the big help.. Kindly put the solution.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140789 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140789\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The equation of the circle with center (1,2) and tangent to <BR>\n" );
document.write( "x+y=1 --> y = -x + 1 (slope m = -1)<BR>\n" );
document.write( "The radius will be thru the point (1,2) and perpendicular to the line x+y=1, so the slope of that radial line will be +1<BR>\n" );
document.write( "y-2 = x-1<BR>\n" );
document.write( "y = x+1 is the eqn of the line thru the center and perpendicular to x+y=1.<BR>\n" );
document.write( "Find the intersection, which is the tangent point.<BR>\n" );
document.write( "x+y=1<BR>\n" );
document.write( "x-y=-1<BR>\n" );
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document.write( "x = 0, y = 1 --> the point (0,1)<BR>\n" );
document.write( "The radius is the distance from (0,1) to (1,2)<BR>\n" );
document.write( "r = sqrt(2)<BR>\n" );
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document.write( "(x-1)^2 + (y-2)^2 = 2 is the circle.\r<BR>\n" );
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