document.write( "Question 187773: I need your help on solving an inequality. I know how to solve it but I don't understand the test points. For example:
\n" ); document.write( "x^2+6x<16
\n" ); document.write( "I know that the problem gets put in standard form
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\n" ); document.write( "and then it is factored
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\n" ); document.write( "then you set the factors equal to zero for the x intercepts
\n" ); document.write( "x+8=0 x=-8 and x-2=0 x=2\r
\n" ); document.write( "\n" ); document.write( "but I don't understand the test points
\n" ); document.write( "for example
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\n" ); document.write( "(-8,2)
\n" ); document.write( "(-8,-2)U (8,8)
\n" ); document.write( "(-8,-8)U (2,8)\r
\n" ); document.write( "\n" ); document.write( "please explain
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Algebra.Com's Answer #140780 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
You're off to a great start. \r
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\n" ); document.write( "\n" ); document.write( "Now construct a number line with the critical values plotted on the line:\r
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\n" ); document.write( "\n" ); document.write( "Notice how there are three regions: \r
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\n" ); document.write( "\n" ); document.write( "Region #1: To the left of the first critical value -8. The region in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Region #2: In between the critical values -8 and 2. The region in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "Region #3: To the right of the second value 2. The region in interval notation is ()\r
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\n" ); document.write( "\n" ); document.write( "For any region, the graph is either above the x-axis or below the x-axis (no region is a mix of the two or on the x-axis). So all we have to do is plug in test points that represent the three regions to find the solution set.\r
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\n" ); document.write( "\n" ); document.write( "Let's see if the first region is part of the solution set.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-2%29%3C0\" Start with the factored expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28-9%2B8%29%28-9-2%29%3C0\" Plug in \"x=-9\" (this value is less than -8 which means that it lies in the first region)\r
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\n" ); document.write( "\n" ); document.write( "\"%28-1%29%28-11%29%3C0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"11%3C0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Since this inequality is FALSE, this means that ANY x value in this region does NOT satisfy \"x%5E2%2B6x%3C16\". So we can ignore this region.\r
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\n" ); document.write( "\n" ); document.write( "Let's see if the second region is part of the solution set.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-2%29%3C0\" Start with the factored expression\r
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\n" ); document.write( "\n" ); document.write( "\"%28-7%2B8%29%28-7-2%29%3C0\" Plug in \"x=-7\" (this value is greater than -8 and less than 2)\r
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\n" ); document.write( "\n" ); document.write( "\"%281%29%28-9%29%3C0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"-9%3C0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Since this inequality is TRUE, this means that ANY x value in this region satisfies \"x%5E2%2B6x%3C16\". So the interval () is part of the solution set.\r
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\n" ); document.write( "\n" ); document.write( "Let's see if the third region is part of the solution set.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B8%29%28x-2%29%3C0\" Start with the factored expression\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2B8%29%283-2%29%3C0\" Plug in \"x=3\" (this value is greater than 2)\r
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\n" ); document.write( "\n" ); document.write( "\"%2811%29%281%29%3C0\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "\"11%3C0\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "Since this inequality is FALSE, this means that ANY x value in this region does NOT satisfy \"x%5E2%2B6x%3C16\". So we can ignore this region.\r
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\n" ); document.write( "\n" ); document.write( "Answer: \r
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\n" ); document.write( "\n" ); document.write( "So the solution set to the inequality \"x%5E2%2B6x%3C16\" is ()\r
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\n" ); document.write( "\n" ); document.write( "If the above did not make any sense, then take a look at the graph of \"y=x%5E2%2B6x-16\"\r
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\n" ); document.write( "\n" ); document.write( "Notice that the x-intercepts are -8 and 2. The portion of the graph to the left of -8 is ALL above the x-axis. The portion in between -8 and 2 is ALL below the x-axis. Finally, the piece from 2 on to infinity is ALL above the x-axis.\r
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\n" ); document.write( "\n" ); document.write( "So the only portion that satisfies \"x%5E2%2B6x-16%3C0\" is from -8 to 2.
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