document.write( "Question 20619: Here is my question:\r
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document.write( "1-logx = log(3x-1)\r
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document.write( "I started with:
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document.write( "1 - logx = log3x - log
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document.write( "1 = log4x - log\r
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document.write( "The answer is 2, but I don't know where to go from here!
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document.write( "Can anyone help?
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document.write( "Thanks!
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document.write( "Sandy \n" );
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Algebra.Com's Answer #14078 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1-logx=log(3x-1) \n" ); document.write( "1=logx+log(3x-1) \n" ); document.write( "You have to know log(AB)=logA+logB \n" ); document.write( "So, 1=log[x(3x-1)] \n" ); document.write( "1=log[3x^2-x] \n" ); document.write( "Assuming the base is 10 you get: \n" ); document.write( "10^1=3x^2-x \n" ); document.write( "3x^2-x-10=0 \n" ); document.write( "(3x+5)(x-2)=0 \n" ); document.write( "x cannot be negative so x=2\r \n" ); document.write( "\n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |