document.write( "Question 187753: In one year, Steve earned the same interest from an investment at 5% annual interest as an investment at 7% annual interest. He invested $1200 less in the 7% account. How much money was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #140778 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .05(X+1200)=.07X \n" ); document.write( ".05X+60=.07X \n" ); document.write( ".05X-.07X=-60 \n" ); document.write( "-.02X=-60 \n" ); document.write( "X=-60/-.02 \n" ); document.write( "X=$3,000 ANS. FOR THE AMOUNT INVESTED @7% \n" ); document.write( "3000+1200=4200 ANS. FOR THE AMOUNT INVESTED @ 5%. \n" ); document.write( "PROOF: \n" ); document.write( ".05*4200=.07*3000 \n" ); document.write( "210=210 \n" ); document.write( " |