document.write( "Question 187753: In one year, Steve earned the same interest from an investment at 5% annual interest as an investment at 7% annual interest. He invested $1200 less in the 7% account. How much money was invested in each account? \n" ); document.write( "
Algebra.Com's Answer #140778 by checkley77(12844)\"\" \"About 
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.05(X+1200)=.07X
\n" ); document.write( ".05X+60=.07X
\n" ); document.write( ".05X-.07X=-60
\n" ); document.write( "-.02X=-60
\n" ); document.write( "X=-60/-.02
\n" ); document.write( "X=$3,000 ANS. FOR THE AMOUNT INVESTED @7%
\n" ); document.write( "3000+1200=4200 ANS. FOR THE AMOUNT INVESTED @ 5%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".05*4200=.07*3000
\n" ); document.write( "210=210
\n" ); document.write( "
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