document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26127>Question 26127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need to know how to solve for x In this equation: Log base x of 8/27=-3 Step by Step Please. Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14077 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take the anti-log of both sides to get <BR>\n" );
document.write( "x^(-3)=(8/27)<BR>\n" );
document.write( "Raise both sides to the -1/3 power to get<BR>\n" );
document.write( "x=(8/27)^(-1/3)<BR>\n" );
document.write( "x=(27/8)^(1/3)<BR>\n" );
document.write( "x=3/2\r<BR>\n" );
document.write( "\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );