document.write( "Question 187755This question is from textbook
\n" );
document.write( ": In a test of a heat-seeking rocket, the target rocket is launched at 2000 ft/sec and the heat-seeking rocket is launched along the same flight path 12 seconds later at a speed of 3200 ft/sec. Find the times t1 and t2 of flight of the rockets until the heat-seeking rocket destroys the first rocket.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #140769 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! In a test of a heat-seeking rocket, the target rocket is launched at 2000 ft/sec \n" ); document.write( " and the heat-seeking rocket is launched along the same flight path 12 seconds \n" ); document.write( " later at a speed of 3200 ft/sec. Find the times t1 and t2 of flight of the \n" ); document.write( " rockets until the heat-seeking rocket destroys the first rocket. \n" ); document.write( ": \n" ); document.write( "From the given information we can say: \n" ); document.write( "t1 = t2 + 12 (seconds) \n" ); document.write( ": \n" ); document.write( "When destruction occurs, both rockets will have traveled the same distance \n" ); document.write( "write a distance equation from this fact: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "2000(t1) = 3200(t2) \n" ); document.write( "t1 = \n" ); document.write( "t1 = 1.6(t2) \n" ); document.write( "Substitute (t2-12) for t1; find t2 \n" ); document.write( "t2 + 12 = 1.6t2 \n" ); document.write( "12 = 1.6t2 - t2 \n" ); document.write( "12 = .6t2 \n" ); document.write( "t2 = \n" ); document.write( "t2 = 20 seconds \n" ); document.write( "then \n" ); document.write( "t1 = 20 + 12 = 32 seconds \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check solution by ensuring they both traveled the same distance \n" ); document.write( "2000 * 32 = 64000 ft \n" ); document.write( "3200 * 20 = 64000 ft also \n" ); document.write( " \n" ); document.write( " |