document.write( "Question 187755This question is from textbook
\n" ); document.write( ": In a test of a heat-seeking rocket, the target rocket is launched at 2000 ft/sec and the heat-seeking rocket is launched along the same flight path 12 seconds later at a speed of 3200 ft/sec. Find the times t1 and t2 of flight of the rockets until the heat-seeking rocket destroys the first rocket.
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Algebra.Com's Answer #140769 by ankor@dixie-net.com(22740)\"\" \"About 
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In a test of a heat-seeking rocket, the target rocket is launched at 2000 ft/sec
\n" ); document.write( " and the heat-seeking rocket is launched along the same flight path 12 seconds
\n" ); document.write( " later at a speed of 3200 ft/sec. Find the times t1 and t2 of flight of the
\n" ); document.write( " rockets until the heat-seeking rocket destroys the first rocket.
\n" ); document.write( ":
\n" ); document.write( "From the given information we can say:
\n" ); document.write( "t1 = t2 + 12 (seconds)
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\n" ); document.write( "When destruction occurs, both rockets will have traveled the same distance
\n" ); document.write( "write a distance equation from this fact: Dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "2000(t1) = 3200(t2)
\n" ); document.write( "t1 = \"%28%283200t2%29%29%2F2000\"
\n" ); document.write( "t1 = 1.6(t2)
\n" ); document.write( "Substitute (t2-12) for t1; find t2
\n" ); document.write( "t2 + 12 = 1.6t2
\n" ); document.write( "12 = 1.6t2 - t2
\n" ); document.write( "12 = .6t2
\n" ); document.write( "t2 = \"12%2F.6\"
\n" ); document.write( "t2 = 20 seconds
\n" ); document.write( "then
\n" ); document.write( "t1 = 20 + 12 = 32 seconds
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\n" ); document.write( "Check solution by ensuring they both traveled the same distance
\n" ); document.write( "2000 * 32 = 64000 ft
\n" ); document.write( "3200 * 20 = 64000 ft also
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