document.write( "Question 187637This question is from textbook mathematical analysis
\n" ); document.write( ": The demand function for an office supply company's line of plasic rulers is p= 0.45- 0.00045q, where p is the price (in dollars) per unit when q units are demanded(per day) by consumers. Find the level of production that will minimize the mufacture's total revenue, and determine this revenue.
\n" ); document.write( "Please with full details, thanks
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Algebra.Com's Answer #140751 by ankor@dixie-net.com(22740)\"\" \"About 
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The demand function for an office supply company's line of plastic rulers is
\n" ); document.write( " p = 0.45 - 0.00045q, where p is the price (in dollars) per unit when q units
\n" ); document.write( " are demanded(per day) by consumers.
\n" ); document.write( "I think it should be:
\n" ); document.write( " Find the level of production that will maximize the manufacturer's total
\n" ); document.write( " revenue, and determine this revenue.
\n" ); document.write( ":
\n" ); document.write( "p = 0.45 - 0.00045q
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\n" ); document.write( "Level of production = q
\n" ); document.write( ":
\n" ); document.write( "Revenue = quantity * price
\n" ); document.write( "r = q * p
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\n" ); document.write( "Replace p with (.45-.00045q) in the above equation and you have
\n" ); document.write( "r = q * (.45-.00045q)
\n" ); document.write( "r = .45q - .00045q^2
\n" ); document.write( "Arrange as a quadratic equation:
\n" ); document.write( "r = -.00045q^2 + .45q
\n" ); document.write( ":
\n" ); document.write( "We can find the value of q which gives max amt by using the eq: x = -b/(2a)
\n" ); document.write( "in this equation that would be
\n" ); document.write( "q = \"%28-.45%29%2F%282%2A-.00045%29\"
\n" ); document.write( "q = \"%28-.45%29%2F%28-.00090%29\"
\n" ); document.write( "q = +500 units need to be produced for max revenue
\n" ); document.write( ":
\n" ); document.write( "Then it says,\"and determine this revenue\"
\n" ); document.write( "Substitute 500 for q in the revenue equation (r = -.00045q^2 + .45q)
\n" ); document.write( "r = -.00045(500^2) + .45(500)
\n" ); document.write( "r = -.00045(250000) + 225
\n" ); document.write( "r = -112.5 + 225
\n" ); document.write( "r = $112.5 is the max revenue and occurs when you produce 500 units
\n" ); document.write( ":
\n" ); document.write( "Did this make sense to you, any questions?
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