document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187735>Question 187735</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radius of the circle x^2+y^2-2x-2y+2=0\r<BR>\n" );
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document.write( "Thanks for the big help.. Kindly put the solution.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140747 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140747\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Standard equation of a circle is:<BR>\n" );
document.write( "(x - h)^2 + (y - k)^2 = r^2<BR>\n" );
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document.write( "We \"complete the square\" to put our equation into the standard form:<BR>\n" );
document.write( "x^2+y^2-2x-2y+2=0<BR>\n" );
document.write( "x^2+y^2-2x-2y = -2<BR>\n" );
document.write( "(x^2-2x)+(y^2-2y) = -2<BR>\n" );
document.write( "(x^2-2x+1)+(y^2-2y+1) = -2+1+1<BR>\n" );
document.write( "(x-1)^2+(y-1)^2 = 0<BR>\n" );
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document.write( "Radius = 0\r<BR>\n" );
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