document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187716>Question 187716</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is fixed at 15cm. What lengths will make the permiter greater than 72 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140742 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = length<BR>\n" );
document.write( "width is given as 15 cm<BR>\n" );
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document.write( "Perimeter = 2(width + length)<BR>\n" );
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document.write( "72 < 2(15+x)<BR>\n" );
document.write( "dividing both sides by 2:<BR>\n" );
document.write( "36 < 15+x<BR>\n" );
document.write( "subtracting both sides by 15:<BR>\n" );
document.write( "21 < x<BR>\n" );
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document.write( "This says that the length has to be \"greater than\" 21 cm.<BR>\n" );
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