document.write( "Question 187698This question is from textbook algebra 1
\n" ); document.write( ": kuya edjones thanks for anwering my question!\r
\n" ); document.write( "\n" ); document.write( "6y-x=-12
\n" ); document.write( "1/6x+y=3\r
\n" ); document.write( "\n" ); document.write( "this is the another given! i try to solve it but the answer is undefind too
\n" ); document.write( " am i correct!??\r
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\n" ); document.write( "\n" ); document.write( "thanks very much!\r
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Algebra.Com's Answer #140731 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
6y-x=-12
\n" ); document.write( "1/6x+y=3
\n" ); document.write( "this is the another given! i try to solve it but the answer is undefind too
\n" ); document.write( "am i correct!??
\n" ); document.write( "---------------
\n" ); document.write( "6y-x=-12
\n" ); document.write( "1/6x+y=3 Assuming you mean x/6, and not 1/(6x), -->x + 6y = 18
\n" ); document.write( "x + 6y = 18
\n" ); document.write( "x - 6y = 12
\n" ); document.write( "-------------- Add the 2 eqns
\n" ); document.write( "2x = 30
\n" ); document.write( "x = 15
\n" ); document.write( "------
\n" ); document.write( "y = 3 - 15/6
\n" ); document.write( "y = 1/2
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