document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=26176>Question 26176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please Help<BR>\n" );
document.write( "A forester mixes gasoline and oil to make 2 gallons of mixture for his two-cycle chain-saw engine.  This mixture is 32 parts gas and 1 part two-cycle oil.  How much gas must be added to bring the mix to 40 parts gas and 1 part oil.  \r<BR>\n" );
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document.write( "Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #14073 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=14073\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let number of gallons of pure gas be \"x\".<BR>\n" );
document.write( "Follow the gas:<BR>\n" );
document.write( "Start with (32/33)(2 gallons)<BR>\n" );
document.write( "Add x gallons<BR>\n" );
document.write( "End up with (40/41)(2+x)gallons<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "(32/33)(2)+x=(40/41)(2+x)<BR>\n" );
document.write( "Multiply through by 33*41 to get:<BR>\n" );
document.write( " 2624 +1353x=2640+1320x<BR>\n" );
document.write( "  33x=16<BR>\n" );
document.write( "x=16/33=0.4848 gallons<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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