document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=187695>Question 187695</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0536944733/algebrahomeworkh>Introductory and Intermediate Algebra</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> Hi i'm trying to work out on the practice Test on my txtbook & i'm not sure with my answer can you please help me...\r<BR>\n" );
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document.write( "48)Denominators are additive inverses.Add pr subtract as indicated.Simplify the result if possible.\r<BR>\n" );
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document.write( "(y-7)/(y^2-16) + (7-y)/(16-y^2)\r<BR>\n" );
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document.write( "I did the cross multiplication<BR>\n" );
document.write( "(16y-y^3-112+7y^2) / (7y^2-y3-112+16y)\r<BR>\n" );
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document.write( "(-y^3 +7y^2 +16y-112)/(-y^3 +7y^2 +16y-112)\r<BR>\n" );
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document.write( "what will be the answer is it 1 or 0?<BR>\n" );
document.write( "Did I do the right thing? or there is another solution?\r<BR>\n" );
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document.write( "Looking forward for your reply.\r<BR>\n" );
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document.write( "Thanks\r<BR>\n" );
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document.write( "KAttie\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #140728 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=140728\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "OK. LET'S SEE.  I'LL DO IT AND THEN WE'LL COMPARE.<BR>\n" );
document.write( "(y-7)/(y^2-16) + (7-y)/(16-y^2) <BR>\n" );
document.write( "Cross multiplying, we get:<BR>\n" );
document.write( "(y-7)(16-y^2)=-y^3+7y^2+16y-112<BR>\n" );
document.write( "(7-y)(y^2-16)=-y^3+7y^2+16y-112<BR>\n" );
document.write( "Now for the denominator:<BR>\n" );
document.write( "(y^2-16)(16-y^2)=-y^4+32y^2-256<BR>\n" );
document.write( "I THINK THIS IS WHERE YOU MAY HAVE GOTTEN OFF TRACK\r<BR>\n" );
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document.write( "Now, putting the numerator and denominator together, we have:<BR>\n" );
document.write( "{Notice, I'm factoring a -2 out of the numerator and a -1 out of the denominator}<BR>\n" );
document.write( "-2(y^3-7y^2-16y+112)/-1(y^4-32y+256) and this equals<BR>\n" );
document.write( "2((y-7)(y^2-16))/(y^2-16)^2 cancel out the (y^2-16) and we get<BR>\n" );
document.write( "2(y-7)/(y^2-16)------------------I think this is the answer\r<BR>\n" );
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document.write( "Look at the second term;  if we factor out -1 from the numerator and denominator, what do we get?<BR>\n" );
document.write( "(y-7)/(y^2-16)+(-1)(y-7)/(-1)(y^2-16)) Whoaaaa!! the -1's cancel and we now have:\r<BR>\n" );
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document.write( "y-7)/(y^2-16)+(y-7)/(y^2-16)) =2(y-7)/(y^2-16)\r<BR>\n" );
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document.write( "Maybe an easier way??? \r<BR>\n" );
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document.write( "Hope this helps, Kattie---ptaylor\r<BR>\n" );
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